a bullet is fired from a gun at a velocity of 25 m per second it strike a stationary board and penetrate 2 cm in it before coming to rest calculate the retardation caused by the board and the time taken to penetrate the boat
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Ans. Given,
initial velocity,u= 25m/s
final velocity,v= 0m/s
displacement in board,s = 2cm or 0.002 m
As we know,
v^2 -u^2 =2as
0 - 625 =2×a×0.002
a =-625/0.004
a= = -1.56 ×10^6 m/s^2
So, the retardation is 1.56×10^6 m/s^2.
Now,
v=u +at
0 = 25-1.56×10^6×t
t= 25/1.56 ×10^6
t=1.6×10^-5 s
Hence, Time taken to penetrate the board is 1.6 ×10^-5
Hope this will help you
initial velocity,u= 25m/s
final velocity,v= 0m/s
displacement in board,s = 2cm or 0.002 m
As we know,
v^2 -u^2 =2as
0 - 625 =2×a×0.002
a =-625/0.004
a= = -1.56 ×10^6 m/s^2
So, the retardation is 1.56×10^6 m/s^2.
Now,
v=u +at
0 = 25-1.56×10^6×t
t= 25/1.56 ×10^6
t=1.6×10^-5 s
Hence, Time taken to penetrate the board is 1.6 ×10^-5
Hope this will help you
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