Physics, asked by Jardhan9292, 6 hours ago

A bullet is fired from a gun . The force on the bullet is given by F = 600 - 2 × 10^5 t , where F is in Newton and t in second . The force on the bullet becomes 0 as soon as it leaves the barrel . What is the impulse imparted to the bullet ? ​

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Answered by ValeryLegasov
2

Answer:

0.9 the explanation is in the image

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