Question

A bullet is fired from a gun with muzzle velocity of 200 m/s at an angle of 60°to the horizontal find range, maximum height​

Answer 1

Answer:

Range ~ 3460m, Maximum height ~ 1500m

Explanation:

use:

$\frac{{u}^{2} \sin(2 \times \alpha )}{g}$

for Range of projectile

and,

$\frac{{u}^{2} \times {\sin( \alpha )}^{2}}{2 \times g}$

for Maximum height

insert all values and you'll get it.