Question

A bullet is fired from a rifle attains a max height of 25 m and crosses a range of 200 m. Find the angle of projection

Answer 1

solution:

$\hbox{we know maximum hight}\\</p><p>h=\frac{u^2sin^2\theta }{2g}=25------(1)\\</p><p>\hbox{ Range R}=\frac{u^2sin2\theta }{200}-------(2)\\</p><p>\hbox {dividing (1)and (2) solving, we get}\\</p><p>8sin\theta = 4cos\theta \\</p><p>tan\theta =\frac{1}{2}\\</p><p>\theta =26.6°$