Question

- A bullet is fired from the gun, it covers maximum horizontal distance of 10 km. Determine the
velocity of projection and the maximum height attained by the bullet.
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Answer 1

Hey Dear,

◆ Answer -

u = 100√10 m/s

H = 2500 m

◆ Explanation -

# Given -

Rmax = 10 km = 10000 m

# Solution -

For maximum horizontal distance, angle of projection should be 45°.

Horizontal range is given -

R = u².sin2θ / g

10000 = u² × sin90° / 10

u² = 100000

u = 100√10 m/s

Maximum height attached by bullet is -

H = u².sin²θ / 2g

H = 100000 × sin²45° / (2 × 10)

H = 5000 × 0.5

H = 2500 m

Hope this helps you ...