Question

A bullet is fired horizontally from the top of a building with speed 100 m/s. the distance which it falls vertically down in first two seconds is

Answer 1

using first eqution of motion

v=u+at
0=100+a×2
a= -50

using 2 equation of motion


s =ut +1/2at^2
=100×2+1/2×(-50)×2^2
= 200--100
=100 m