Question

A bullet is fired horizontally with a velocity of 80m/s. During the first second it falls _____?

Explain me by writting in a paper only..​

Answer 1

Answer:

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Answer 2

Answer:

It falls by a distance of 4.9m during first second.

Explanation:

Given that,

A bullet is fired horizontally with a velocity of 80m/s.

We need to find the distance it falls by during first second.For that we use the kinematic equation

$s = ut + \frac{1}{2} at {}^{2}$

Here,u=0,a=-g&t=1 sec

Therefore,

$s = 0 \times 1 + \frac{1}{2} ( - 9.81)(1 {}^{2} ) \\ = - 4.9m$

(Negative sign indicates displacement in downward direction)

Therefore it falls by a distance of 4.9m during first second

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