Question

a bullet is fired in a horizontal direction with a muzzle velocity 300m/s in the absence of air resistance how far will it have dropped in travelling a horizontal distance of 150m. take g=10m/s^​

Answer 1

Given:

A bullet is fired in a horizontal direction with a muzzle velocity 300m/s.

To find:

Height dropped after travelling 150 m distance.

Calculation:

Let time taken to travel 150 m be t ;

$x = v \times t$

$= > 300 = 150 \times t$

$= > t = 2 \: sec$

So, height dropped be h ;

$\therefore \: h = u_{y}t + \dfrac{1}{2} g {t}^{2}$

$= > \: h = (0 \times t )+ \dfrac{1}{2} g {t}^{2}$

$= > \: h = \dfrac{1}{2} g {t}^{2}$

$= > \: h = \dfrac{1}{2} \times 10 \times {(2)}^{2}$

$= > \: h = 5 \times {(2)}^{2}$

$= > \: h = 5 \times 4$

$= > \: h = 20 \: m$

So , final answer is:

$\boxed{ \sf{ \large{ \: height \: dropped = 20 \: m}}}$