A bullet is fired in a horizontal direction with a muzzle velocity of 300m\s. In the absence of air resistance, how far will it have dropped in travelling a distance of:
a)20m. (b)40m (c) 60m. (d) How far will it drop in one second
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Answer:
(a) S = ut+1/2at² (a=0)
S=ut
t= s/u
t= 20/300
t= 0.067 sec
h= ut+1/2gt² ( u=0)
h= 1/2*5*(0.067)²
h= 0.022 m
(b)s should be equal to 40m
(c) S = 60m
(d) h=ut+1/2gt² (u=0)
h=1/2gt² (g=9.8 or 10)
h= 1/2*9.8*1
h= 4.9m ( if g=10, h=5m)
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