Question

a bullet is fired into a wall with a velocity of 50 M / S if the bullet stops at a depth of 10 cm inside the wall find the retardation provided by the wall

Answer 1

Given,

Initial velocity u = 50 m/s

Final velocity v = 0

Distance s = 10 cm

= 0.1 m

We know that,

v² = u² + 2as

a = -u² / 2s

a = -2500 / (0.2)

a = -12500 m/s²

So, retardation = 12500 m/s² Ans.

Answer 2

Answer:

The retardation provided by the wall is 12500m/s².

Explanation:

From the third equation of motion we have,

$v^2-u^2=2as$       (1)

Where,

v=final velocity

u=initial velocity

a=acceleration of the object

s=distance traveled by an object

From question,

u=50m/s

Depth the bullet travels(s)=10cm=0.1m

v=0 (the bullet stops after traveling the depth of 10cm)

By substituting u,v, and s in equation (1) we get;

$(0)^2-(50)^2=2\times a\times 0.1$

$a=\frac{-2500}{0.2}=-12500m/s^2$    (here negative sign indicates that acceleration is decreasing i.e.retardation)

Hence, the retardation provided by the wall is 12500m/s².