A bullet is fired on a wall with a velocity of 100 m/s. If the bullet stops at a depth of 10 cm inside the wall, then the retardation provided by the wall is ?
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If the bullet stops at a depth of 10cm inside the wall, then find the retardation produced by the wall. Answer (a= -50000m/s)
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Given :-
Initial velocity of bullet is 100m/s
Final velocity of bullet is 0m/s
Distance travelled by bullet is 10cm = 0.1m
To Find :-
Retardation [ Negative acceleration ]
Solution :-
❍ To calculate the acceleration we have to substitute the values in the third equation of motion ::
v² = u² + 2as
Where,
- v is final velocity
- u is initial velocity
- a is acceleration
- s is distance
⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━
Finding acceleration :-
⤳ 0² = 100² + 2as
⤳ 0² = 100² + [ 2a × 0.1 ]
⤳ 0² = 100² + 0.2a
⤳ 0 = 10000 + 0.2a
⤳ 0.2a = 0 - 10000
⤳ 0.2a = -10000
⤳ a = -10000/0.2
⤳ a = -10000/2
⤳ a = -5000 m/s
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- Henceforth, the retardation is -5000m/s
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