A bullet is fired onto a wall with a velocity of 30m/s.if the bullet stops at a depth of 10 cm in a wall find the retardation produced by wall
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here initial velocity,u=30m s^-1
Since,The bullet is stopped after reaching a depth of 10cm
Therefore, final velocity is 0
and the distance travelled ,s=10cm=0.1m
Now, according to 3rd eqn of motion
v^2 -u^2= 2as
Therefore, by equating this we get ,
delelaration,a=-4500m s^-2
Since,The bullet is stopped after reaching a depth of 10cm
Therefore, final velocity is 0
and the distance travelled ,s=10cm=0.1m
Now, according to 3rd eqn of motion
v^2 -u^2= 2as
Therefore, by equating this we get ,
delelaration,a=-4500m s^-2
Answered by
1
Answer:
here initial velocity,u=30m s^-1
Since,The bullet is stopped after reaching a depth of 10cm
Therefore, final velocity is 0
and the distance travelled ,s=10cm=0.1m
Now, according to 3rd eqn of motion
v^2 -u^2= 2as
Therefore, by equating this we get ,
,a=-4500m s^-2
Explanation:
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