Question

A bullet is fired vertically upwards from a gun held 2m above the ground, reaches its maximum height in 4 sec. Calculate the i) Magnitude of the initial velocity of the bullet. ii) Total distance the bullet travelled by the time it hits the ground. ( g = 10m/s² )​

Answer 1

Explanation:

djjdjdjdjdjdjxxjdjddjjd

Answer 2

First we need to know the initial velocity of the bullet.

v(t)=v(0)−gtv(4)=0v(0)=4g

By conservation of energy, the energy reaches its apex equals the energy when the bullet leaves the gun.

12mv2=mgh12m(4g)2=mghh=8g

This is the distance above the the gun.

Total distance, will be the disance up plus the distance down plus the distance the gun is above the floor.

16g+2