Question

A bullet is fired vertically upwards with a velocity of 196 m/sec. What is maximum height reached by the bullet

Answer 1

Answer:

1960 m

Explanation:

According to the given question,

u = initial velocity = 196 m/s

v = final velocity = 0 m/s

As at top most point velocity of bullet becomes zero.

g = acceleration due to gravity = 9.8 m/s^2

h = Maximum Height

And we are asked to find the Maximum height.

Now,

• v^2 = u^2 - 2gh

• v^2 - u^2 = - 2gh

• h = (v^2 - u^2)/-2g

• h = (u^2-v^2)/2g

Putting the values we get,

• h = (196)^2 - 0 / 2×9.8

• h = 196×196/2×9.8

• h = 38416/19.6

• h = 1960 m

Thus maximum height that bullet will cover is 1960 m when it's initial velocity is 196 m/s .

Answer 2

PARABOLIC MOTION :

Solution :

Velocity, $\mathsf{v_0}$ = 196 m/sec

Maximum height reached, H = $\mathsf{\dfrac{{v_0}^{2}}{2g}}$

H = $\mathsf{\dfrac{{196}^{2}}{2*9.8}}$

H = $\mathsf{\dfrac{{196}^{2}}{19.6}}$

H = 1960 m.

Hence, Maximum height reached by the bullet is 1960m.