Question

A bullet is fired vertically upwards with an initial velocity of 50ms-'. It covers a distance h1 during the
first second and a distance h2 during the last 3 seconds of its upward motion. If g = 10ms? h1 and h2
will be related as:
A) h1 = 3h2
B) h1 = 2h2
C) h1 = h2
D) h1=h2/3​

Answer 1

hope it will help uhh........

Answer 2

Answer:h2=h1

Explanation:at highest level v=0

V=u+gt

=50+-10t

Then t=50/10=5

Time of ascent =time of descent

Thus displacement covered by last 3 sec=displacement coverd by 1st 3 sec from the top

Then s=ut+1/2at^2

=0+1/2*10*9=45m

Displacement covered by 1st sec! S,=ut+1/2-gt^2

=50*1+1/2*-10*1=45m

Thus h1=h2