Question

A bullet is fired vertically upwards with an initial velocity of 50 ms^-1 .if g=10 ms^-2 what is ratio of distance travelled by bullet during first and last second of upward motion

Answer 1

in the first second use

s= ut+ 1/2 at2 , a is negative here
= 50*1 - 1/2 * 10 * 12
= 50 - 5 = h1 = 45m

​time of ascend = u/g = 50/10 = 5s

 distance travelled in last 3 seconds = total distance - distance travelled in first 2 seconds

=> u2/2g - ( ut-1/2at2)
=  125- (100- 20)
= 125-80= 45

h1:h2:: 45:45=1:1

Answer 2

Answer:

1:1

Explanation: