Question

a bullet is fired With 100 m/sec towards a wooden block and aftee enterning in wooden block when it covers 2 cm distance its velocity decreases by 50%.Find distance covered bullet after it comes to rest​

Answer 1

Answer:

2.6cm

Explanation:

We have,

u = 100m/s

v = 50m/s (after 2cm)

Now let's find acceleration,

2as = v^2 - u^2

⇒ 2a×0.02 = 2500-10000

⇒ 0.04a = -7500

⇒ a = -187500

So, the acceleration is -187500 m/s^2

Now find distance covered by bullet after it comes to rest​,

2as = v^2 - u^2

⇒ 2×-187500*s = 0-10000

⇒-375000s = -10000

⇒ s = 0.026

Hence, the distance covered by bullet after it comes to rest​ is 2.6 cm (0.026m).

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