Question

A bullet is fired with a speed of 1000 m/s in order to hit a target 100 m away .If g=10m/s^2 the gun should be aimed at

Answer 1

Hey!

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Distance (s) of target = 100 m
Speed (v) = 1000 m/s
I

Time (t) = Distance / Time
= 100 / 1000
= 0.1 s

Distance travelled by the bullet = ?

s = ut + 1/2 at^2

Initial velocity = u
Acceleration due to gravity = 10 m/s^2

s = 0 × 0.1 + 1/2 × 10 × (0.1)^2

s = 1/2 × 10 × 0.01

s = 0.05 m

s = 5 cm

So, gun should be aimed at 5 cm or 0.05 m.

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Hope it helps.....!!!

Answer 2

$\boxed {\mathfrak {Hello \: There}}$

• Given :-

• Distance of the target , s = 100 m
• Speed of the bullet , v = 1000 m/s

Now it will be easy to find the time ,

$\bf \: we \: know : \\ \\ \boxed {\bf \: v = \frac{s}{t} } \rightarrow \bf t = \frac{100 }{1000} = \frac{1}{10 s}$

$\bf \: Now \: Using \: the \: second \: equation \\ \bf of \: motion \: to \: find \: out \: the \\ \bf \: distance \: travelled by the bullet \\ \\ \boxed{ \bf s = ut + \frac{1}{2} \times a {t}^{2} } \\ \\ = 0 \times \frac{1}{10} + \frac{1}{2} \times 10 \times \frac{1}{100} \\ \\ = \frac{5}{100} \\ \\ \boxed{ \bf \: s \: = \: 0 .05 \: m}$

$\boxed {\mathfrak {Hence \: the \: gun \: should \: be \: target \: at \: 0.05 \: m }} \\ \\ \bf \: Good \: luck :)$