Question

a bullet is fired with a speed of 200m/s at an angle 30°, what is its height after 5 second​

Answer 1

Explanation:

Given that,

Speed of bullet = 2000 m/s

Distance = 200 m

Now,

v=

t

D

t=

v

D

t=

2000

200

t=0.1s

Now, distance covered by bullet vertically in that time

s=ut+

2

1

at

2

s=0+0.5×10×(0.1)

2

s=0.05m

s=5cm

Hence, the bullet should be fired 5 cm above the target.

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Hope it will help you.