Question

A bullet is fired with a velocity of 10 m/s in a direction making

an angle of 300with the vertical. Calculate its time of flight and

the maximum height reached by it.?​

Answer 1

Answer:

Given : v=10 m/s

Angle of projection θ=90−30=60

o

Time of flight T=

g

2vsinθ

=

10

2×10×(

3

/2)

=

3

s

Maximum height reached h=

2g

v

2

sin

2

θ

=

2×10

10

2

×(

3

/2)

2

=3.75 m

Explanation:

mark me brainliest ☺️