Question

A bullet is fired with a velocity of 39.2 ms. At what angle the bullet should be fired so that it strikes the target at a distance of 78.4 m​ ????

Answer 1

Answer:  

• 15°.

Explanation:  

We know :-  

Horizontal rage of projectile:    

• H = u².sin2θ / g

Substituting the values, we get:-

⇒ 78.4 = 39.2² × sin2θ / 9.8  

⇒ sin2θ = 78.4 × 9.8 / 39.2²    

⇒ sin2θ = 1/2

⇒ 2θ = sin(1/2)  

⇒ 2θ = 30°  

⇒ θ = 15°

∴ The gun should be fired at 15° for the shell to strike its target.

Answer 2

Answer:

(39.2ms−1,45∘) is the answer