Question

A bullet is fired with a velocity of 50m/s at an angle to the horizontal, what is the value of angle and calculate the maximum range

Answer 1

angle of inclination is 45° and maximum range is 50m

we know, Range = u²sin2θ/g

where u is initial velocity of projectile, θ is angle made by projectile with horizontal and g is acceleration due to gravity.

horizontal range will be maximum when sin2θ = 1 = sin90°

⇒θ = 45°

now maximum range = u²sin2(45°)/g = u²/g

= (50)²/10 = 500/10

= 50 m

hence maximum range is 50m

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Answer 2

$\huge\bold\purple{Answer:-}$

we know, Range = u²sin2θ/g

where u is initial velocity of projectile, θ is angle made by projectile with horizontal and g is acceleration due to gravity.

horizontal range will be maximum when sin2θ = 1 = sin90°

⇒θ = 45°

now maximum range = u²sin2(45°)/g = u²/g

= (50)²/10 = 500/10

= 50 m

hence maximum range is 50m