A bullet is fired with a velocity u making an angle of 60° with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is
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Answer→ u/2
The moment when bullet is fired it's horizontal component is ucos60°
and it must be known that horizontal component don't have acceleration in such cases hence the velocity in horizontal component will never change as a result the velocity in horizontal direction will remain constant throughout the projectile.
Hence it will be ucos60°→ u/2
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