a bullet is fired with an angle of 60 with 100 m/s velocity the vertical component of velocity after 2 sec is
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initial velocity = u cos 60°= 100 * 1/2= 50 m/s
now by using the below equation, we get-
v= u-gt. ( here g is taken negative because the motion of the bullet is against gravity)
so, v= 50-10*2
v= 50-20
v= 30m/s
So, the vertical component of velocity after 2 sec will be 30 m/s.
now by using the below equation, we get-
v= u-gt. ( here g is taken negative because the motion of the bullet is against gravity)
so, v= 50-10*2
v= 50-20
v= 30m/s
So, the vertical component of velocity after 2 sec will be 30 m/s.
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