Question

A bullet is moving at a speed 40m/s when it embeds into lumps on a sponge wall.
The bullet penerates with the acceleration of 100m/s2 and then it stops.
How much distance travelled by the bullet ( assume a uniform acceleration)

Answer 1

Answer: 2

Explanation:

Here, the initial velocity of the bullet is u=367m/s and the final velocity is v=0m/s.

Distance traveled by a bullet is d=0.0621m

If a be the acceleration of the bullet.

Using v

2

−u

2

=2ad

0

2

−(367)

2

=2a(0.0621)

⟹ a=−1.08×10

−6

m/s

2

(negative sign indicates deceleration of bullet means it slows down).

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