A bullet is moving at a speed of 367 m/s when it embeds into a lump
of moist clay. The bullet penetrates for a distance of 0.0621 m.
Determine the acceleration of the bullet while moving into the clay
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Answered by
2
Explanation:
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A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay The bullet penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving into the clay (Assume a uniform acceleration.)
Given:
vi = 367 m/s
vf = 0 m/s
d = 0.0621 m
Find:
a = ??
vf2 = vi2 + 2*a*d
(0 m/s)2 = (367 m/s)2 + 2*(a)*(0.0621 m)
0 m2/s2 = (134689 m2/s2) + (0.1242 m)*a
-134689 m2/s2 = (0.1242 m)*a
(-134689 m2/s2)/(0.1242 m) = a
a = -1.08*106 m /s2
(The - sign indicates that the bullet slowed down.)
Answered by
2
Explanation:
-1.08× 10^6 m/s²
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