Question

A bullet is moving at a speed of 367 m/sec when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration).​

Answer 1

Answer:

1.08×10

6

s

2

m

Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.

Distance traveled by bullet is d=0.0621m

If a be the acceleration of bullet.

Using v

2

−u

2

=2ad

0

2

−(367)

2

=2a(0.0621)

⟹ a=−1.08×10

−6

m/s

2

(negative sign indicates deceleration of bullet means it slows down).

Explanation:

1.08×10

6

s

2

m

Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.

Distance traveled by bullet is d=0.0621m

If a be the acceleration of bullet.

Using v

2

−u

2

=2ad

0

2

−(367)

2

=2a(0.0621)

⟹ a=−1.08×10

−6

m/s

2

(negative sign indicates deceleration of bullet means it slows down).