Question

A bullet is moving at a speed of 367m/s when it embeds into a lump of moist clay. The bullet
penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving
into the clay.

Answer 1

Explanation:

Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.

Distance traveled by bullet is d=0.0621m

If a be the acceleration of bullet.

Using v2−u2=2ad

02−(367)2=2a(0.0621)

⟹ a=−1.08×10−6m/s2

(negative sign indicates deceleration of bullet means it slows down).