Question

a bullet is moving at the speed of 40m s when it embeds into a lumps on a sponge wall the buttet penetrates withe acceleration of 100 m s and then it stops how much distance travelled by the bullet assume a uniform acceleration

Answer 1

$\bf\small\red{Given:-}$

• u = intial velocity of bullet = 40 m/s.

• a = retardation of bullet = -100 m/s.

• v = 0 = final velocity of bullet.

$\bf\small\red{Find:-}$

• S = Distance covered by bullet.

$\bf\small\red{Solution:-}$

we know,

$\rm \rightarrow {v}^{2} = {u}^{2} + 2as$

$\rm\rightarrow \: ( {0}) ^{2} = (40) ^{2} + 2( - 100) \times s$

$\rm\rightarrow - 1600 - 200s$

$\rm\rightarrow \: \frac{1600}{200} = s$

$\rm\rightarrow \purple{8 \: metres}$

@Shivamthakur