Question

A bullet is moving with a speed of 150m/s strikes a tree and penetrate 3.5cm before stopping.what is the magnitude of its acceleration and time taken for to stop the bullet?

Answer 1

Answer:

Explanation:

we take:-

intial velocity = 150m/s = u

final velocity = 0 = v

distance = 3.5cm = S

acceleration = ? = a

so using :

v^2 - u^2 = 2*a*S

so ,

(0)^2 - (150)^2 = 2*3.5*a

0 - 22,500 = 7*a

-22500/7 = a

-3214.28 m/s^2 = a

or

retardation = 3214.28 m/s^2  

ALL THE BEST