A bullet is moving with a speed of 200 m/s. If its kinetic energy is 10⁵ J. Then its mass will be
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3
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★ Gɪᴠᴇɴ :-
- Speed of bullet = 200 m/s
- Kinetic energy ( K.E ) = 10⁵J
__________________________
★ Tᴏ Fɪɴᴅ :-
- Mass of bullet = ?
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★ Sᴏʟᴜᴛɪᴏɴ :-
Finding mass of bullet using ,
K.E = 1/2 mv²
Where
- K.E → kinetic energy = 10⁵ J
- m → mass = ?
- v → speed = 200 m/s
Substituting the values we have,
➽ 10⁵ = 1/2 × (m) × (200)²
➽ 2 × 10⁵ = 40000m
➽ 2 × 100000 = 40000m
➽ 200000 = 40000m
➽ m = 200000 ÷ 40000
➽ Mass of bullet = 5 kg
Hence , mass of bullet = 5 kg
__________________________
Answered by
0
Answer:
Gɪᴠᴇɴ :-
Speed of bullet = 200 m/s
Kinetic energy ( K.E ) = 10⁵J
Tᴏ Fɪɴᴅ :-
Mass of bullet = ?
Finding mass of bullet using ,
K.E = 1/2 mv²
Where
K.E → kinetic energy = 10⁵ J
m → mass = ?
v → speed = 200 m/s
Substituting the values we have,
10⁵ = 1/2 × (m) × (200)²
2 × 10⁵ = 40000m
2 × 100000 = 40000m
200000 = 40000m
m = 200000 ÷ 40000
Mass of bullet = 5 kg
Hence , mass of bullet = 5 kg
THANKS
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