Question

a bullet is moving with a speed of 400m/s. it penetrate a distance of 5 cm into a wooden block and stops. what will be the average force exerted by the bullet on the block. if mass of bullet is 40 g​

Answer 1

here is the answer of ur problem

Answer 2

Answer:

The force exerted is -64000N

Explanation:

The mass of bullet is given as 40 grams which is equivalent to .04kg,  also the speed of bullet is given As 400 metre per second does the bullet penetrates the wooden block block exerts resistive force on the bullet.

As we know is the product of mass and acceleration so we need to find the value of acceleration first

$\bold{\mathrm{v}^{2}-\mathrm{u}^{2}=2 \mathrm{as}}$

0-400x400 = 2x ax(0.05)

a= -1600000 m/s2

f = m x a

F = 0.04 x -1600000 = -64000N