Physics, asked by rishontt, 15 days ago

A bullet is moving with a velocity 20m/s. It strikes a target and comes to rest after penetrating a distance of 10 cm in the target. Calculate the resistive force offered by the target.

Answers

Answered by DSR50
2

\huge{\boxed{\boxed{\red{A}{N}{\blue{S}{\red{W}{\green{E}{R}}}}}}}

Given:

  • u = \tt{20\:ms}^{-1}
  • v = \tt{0}
  • s = \tt{10 \: cm = 0.1 \: m}

Let Retardation be \tt{a}

  • \tt{{v}^{2} = {u}^{2} - 2as}
  • \tt{0 = {(20)}^{2} - (2 \times a \times 0.1)}
  • \tt{a = \boxed{\tt{\frac{400}{2} {ms}^{-2}}}}

  • \huge{\boxed{\boxed{\tt{200\:{ ms}^{-2}}}}}

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