A bullet is projected upwards from the top of a tower height 90m with the velocity 30m/s
making an angle 30° with the horizontal.The time taken by it to reach the ground is
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Answer:
6 sec
Explanation:
A bullet is projected upwards from the top of a tower height 90m with the velocity 30m/s making an angle 30° with the horizontal.The time taken by it to reach the ground is
Horizontal Velcoity = 30Cos30 = 15√3 m/s
Vertical Velcoity = 30Sin30 = 15 m/s
Time taken to reach at top using V = U + at
=> 0 = 15 -10*t
=> t = 1.5 sec
Vertical Distance Covered = 15*1.5 - (1/2)(10)1.5² = 11.25 m
Height = 90 + 11.25 = 101.25
Time to Reach groung
101,25 = (1/2)(10)t²
=> t = 4.5 sec
Total Time of Travel = 1.5 + 4.5 = 6 sec
.The time taken by it to reach the ground is 6 sec
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