Question

A bullet leaves a rifel with a muzzle velocity of 521 m/s.
While accelerating through the barrel of the rifles, the bullet moves a distance of 0.840 m.
Determine the acceleration of the bullet with uniform acceleration.....

Answer 1

Answer: a = 1.62*105 m /s^2

Given:

vi = 0 m/s

vf = 521 m/s

d = 0.840 m

To Find:

a = ??

Solution

vf^2 = vi^2 + 2*a*d

(521 m/s)^2 = (0 m/s)^2 + 2*(a)*(0.840 m)

271441 m^2/s^2 = (0 m/s)^2 + (1.68 m)*a

(271441 m^2/s^2)/(1.68 m) = a

a = 1.62*105 m /s^2

Answer 2

Answer:

Answer: a = 1.62*105 m /s^2

Step-by-step explanation:

Given:

• $\longmapsto$ vi = 0 m/s
• $\longmapsto$ vf = 521 m/s
• $\longmapsto$ d = 0.840 m

To Find:

• $\longmapsto$ a = ??

Solution

$\longmapsto$ vf^2 = vi^2 + 2*a*d

$\longmapsto$ (521 m/s)^2 = (0 m/s)^2 + 2*(a)*(0.840 m)

$\longmapsto$ 271441 m^2/s^2 = (0 m/s)^2 + (1.68 m)*a

$\longmapsto$ (271441 m^2/s^2)/(1.68 m) = a

$\longmapsto$ a = 1.62*105 m /s^2