A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the
rille, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform
acceleration)
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v =1042 m/s
S=1.680 m
Using third equation of motion:-v2-u2 = 2as
v2-u22as 1042 m/s 0 2a x 1.6880 a 1042 x 1042/2 x 1.680 a 1085764/3.36 a 323144.04 m/s2 Acceleration of the bullet is 323144.0m
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