Physics, asked by divijsain23, 8 months ago

A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1680 m. Determine the acceleration of the bullet (assume a uniform acceleration)

Answers

Answered by lucksri789
1

Answer:

Given that, a bullet leaves a rifle with a muzzle velocity of 1042 m/s.

(Initial velocity i.e. u of the bullet is 0 m/s and final velocity i.e. v of the bullet is 1042 m/s.)

Also, while accelerating through the barrel of therifle, the bullet moves a distance of 1680 m. (s = 1680 m)

We have to find the acceleration of the bullet.

Using the Third Equation Of Motion,

v² - u² = 2as

From the above data we have, u = 0/s, v = 1042 m/s and s = 1680.

Substitute the known values in the above formula,

→ (1042)² - (0)² = 2 × a × 1680

→ 1085764 - 0 = 3360a

→ 1085764 = 3360a

Divide by 3360 on both sides,

→ 1085764/3360 = 3360a/3360

→ 323.14 = a

→ a = 323.14

Therefore, the acceleration of the bullet is 323.14 m/s².

Answered by leelakrishnaiah
0

Answer:

647.20m/s

Explanation:

v=1042m/s

d=1680m

a=?

s=d×t

t=d÷s

1680÷1042

1.61s

a=v÷t

1042÷1.61

647.20m/s

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