A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1680 m. Determine the acceleration of the bullet (assume a uniform acceleration)
Answers
Answer:
Given that, a bullet leaves a rifle with a muzzle velocity of 1042 m/s.
(Initial velocity i.e. u of the bullet is 0 m/s and final velocity i.e. v of the bullet is 1042 m/s.)
Also, while accelerating through the barrel of therifle, the bullet moves a distance of 1680 m. (s = 1680 m)
We have to find the acceleration of the bullet.
Using the Third Equation Of Motion,
v² - u² = 2as
From the above data we have, u = 0/s, v = 1042 m/s and s = 1680.
Substitute the known values in the above formula,
→ (1042)² - (0)² = 2 × a × 1680
→ 1085764 - 0 = 3360a
→ 1085764 = 3360a
Divide by 3360 on both sides,
→ 1085764/3360 = 3360a/3360
→ 323.14 = a
→ a = 323.14
Therefore, the acceleration of the bullet is 323.14 m/s².
Answer:
647.20m/s
Explanation:
v=1042m/s
d=1680m
a=?
s=d×t
t=d÷s
1680÷1042
1.61s
a=v÷t
1042÷1.61
647.20m/s