Question

A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform acceleration)

Answer 1

take final speed=1042m/s and u=0 s=1.680 then use ran V^2-U^2=2AS

Answer 2

Answer:-

= 323144.04 m/s²

Given

u = 0

 v = 1042 m/s

s = 1.680 m

Using third equation of motion:-v²-u² = 2as

⇒v²-u² = 2as

⇒1042 m/s² - 0 = 2a × 1.680

⇒ a = 1042 × 1042/2 × 1.680

⇒ a = 1085764/3.36

⇒ a = 323144.04 m/s²

Acceleration of the bullet is 323144.04 m/s²