A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform acceleration)
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Explanation:
We assume the bullet leaves from rest. So the initial velocity will be, u=0m/s
Also given, final velocity v=521m/s and distance traveled d=0.840m
Let a be the acceleration of the bullet.
Using v
2
−u
2
=2ad, we get
(521)
2
−0
2
=2a(0.840)
⟹ a=1.62×10
5
m/s
2
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Answer:
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