Question

A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform acceleration)

Answer 1

u = 0 m/s, v= 521 m/s.  

This means that a = (v^2 - u^2)/2s.  

This is a reformat of v^2 = u^2 + 2as  

a = (521^2)/(2 x 0.840)  

a = 161.57 m/s^2

hope its help you

Answer 2

Here is your answer

u=0 m/s

v= 1042 m/s

s= 1.680 m

Using the formula-

${v}^{2}= {u}^{2} + 2as$

we get,

${1042}^{2}= {0}^{2} + 2×a× 1.680$

$(1042×1042)/(2×1.680)= a$

$<b>a= 323144 m/s^2</b>$

HOPE IT IS USEFUL