Question

. A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform acceleration)

Answer 1

u = 0 m/s, v= 521 m/s.  

This means that a = (v^2 - u^2)/2s.  

This is a reformat of v^2 = u^2 + 2as  

a = (521^2)/(2 x 0.840)  

a = 161.57 m/s^2

Answer 2

Hey friend

here is your answer

given initial velocity is 0

and final velocity is 1042m/s

distance given =1.68 m

v²= U² + 2as

(1042)² = 0 +2a(1.68)

1085764 = 0 +3.36a

its acceleration become

=> 323144 m/s²

Hope it help

Thank you