Question

A bullet leaves a rifle with a muzzle velocity of 1042 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 1.680 m. Determine the acceleration of the bullet (assume a uniform acceleration)

Answer 1

Answer

Given:-

Initial velocity of the bullet, u = 0

Final velocity of the bullet, v = 1042 m/s

Distance covered by the bullet, s = 1.680 m

Acceleration of the bullet = ???

In this question, we have to use third equation of motion

that is  v² = u² + 2as

⇒  v² = u² + 2as

⇒ (1042m/s)²= (0)+ 2a × 1.680 m

⇒ a = 1042m/s²/ 2 × 1.680

⇒ a = 1085764/3.36

⇒ a = 323144.04 m/s²

Explaination:-

The first equation of motion gives the final velocity after a time  for these objects, given an initial velocity .

The second equation of motion gives the displacement of an object under constant acceleration:.

The third equation of motion gives the final velocity of an object under uniform acceleration given the distance traveled and an initial velocity.

Answer 2

$\huge\red{Answer}$

The question states that 0.840 m is the distance travelled within the barrel. Therefore u = 0 m/s, v= 521 m/s. 

This means that a = (v^2 - u^2)/2s. 

This is a reformat of v^2 = u^2 + 2as 

a = (521^2)/(2 x 0.840) 

a = 161.57 m/s^2

HOPE IT HELPS YOU !!