Question

A bullet leaves a rifle with a muzzle velocity of 521m/s. While accelerating through the barrel of the riffle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration).

Answer 1

u=521 m/s
s=.840 m
v=0
v square-u square =2as
0^2-521^521=2a^0.840
-271441=1.68a
a=-161572

Answer 2

Given:

A bullet leaves a rifle with a velocity of 521m/s. It moves a distance of 0.840m while accelerating uniformly in the barrel.

To Find:

The acceleration of the bullet in the rifle.

Solution:

Here, the bullet is starting from rest.

So, the initial velocity of the bullet, $u=0$

It leaves the rifle with a velocity, $v=521m/s$

While accelerating through the barrel with a uniform acceleration $a$, it traverses a distance, $s=0.840m$

Using the equation of uniformly accelerated motion,

    $v^2-u^2=2as$

⇒ $(521)^2-(0)^2=2a(0.840)$

⇒ $a=\frac{271441}{1.68}$

⇒ $a=161572m/s^2$

Hence, the acceleration of the bullet inside the barrel is equal to $161572m/s^2$.