A bullet leaves a rifle with a muzzle velocity of 521m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840m. Determine the acceleration of the bullet (assume a uniform acceleration).
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The question states that 0.840 m is the distance travelled within the barrel. Therefore u = 0 m/s, v= 521 m/s.
This means that a = (v² - u²)/2s.
This is a reformat of v² = u²+ 2as
a = (521^2)/(2 x 0.840)
a = 161.57 m/s²
HOPE IT HELPS U.
#BE BRAINLY.
The question states that 0.840 m is the distance travelled within the barrel. Therefore u = 0 m/s, v= 521 m/s.
This means that a = (v² - u²)/2s.
This is a reformat of v² = u²+ 2as
a = (521^2)/(2 x 0.840)
a = 161.57 m/s²
HOPE IT HELPS U.
#BE BRAINLY.
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