Question

A bullet leaves a rifle with a velocity of 100 m/sec and rifle of mass 2.5 kg recoils with a velocity of 1 m per second .Find the mass of bullet

Answer 1

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$Velocity \: of \: bullet \: (v1) = 100m/ \: sec \\ \\ Mass \: of \: rifle \: (m2) = 2.5kg \\ \\ Velocity \: of \: rifle \: (v2) = 1m/ \: sec \\ \\ we \: have \: to \: find \: the \: Mass \: of \: bullet \: (m1) \\ \\ Now, \: Acc .to \: the \: law \: of \: conservation \: of \: momentum : \\ \\ = > m1v1 = m2v2 \\ \\ = > m1 = \frac{m2v2}{v1} \\ \\ = > m1 = \frac{2.5(1)}{100} \\ \\ = > m1 = \frac{25}{1000} \\ \\ = > m1 = 0.025kg \\ \\ So ,\: The \: Mass \: of \: bullet \: is \: 0.025kg \: or \: 25g$
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Answer 2

Answer:

hope you got your answer

Explanation:

According to conservation of momentum

m1v1 = m2v2

m1 = m2v2 / v1

m1 = (2.5 * 1) / 100

m1 = 0.025kg

m1 = 25g

Mass of bullet is 25g