Question

a bullet leaves a rifle with a velocity of 100m/s and the rifle of mass 2.5 kg recoils with a velocity of 1m/s. find the mass of the bullet

Answer 1

Answer:

According to conservation of momentum

m1v1 = m2v2

m1 = m2v2 / v1

m1 = (2.5 * 1) / 100

m1 = 0.025kg

m1 = 25g

Mass of bullet is 25g

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Answer 2

To Find :

⠀⠀⠀⠀⠀↝ Mass of the bullet.

Solution :

⠀⠀⠀↝mass of rifle = 2.5 kg

⠀⠀⠀↝ velocity of rifle = 1m/s

⠀⠀⠀↝ velocity of bullet = 100m/s

According To conservation of momentum :

❍ Momentum of rifle = Momentum of bullet

$\dag \sf \red{❍ \: m_1v_1 = m_2v_2} \\ \\ \frak{here}\begin{cases}\sf{ \bullet \: m_1 = mass \: of \: bullet}\\\sf{ \bullet \: m_2 = mass \: of \: rifle}\\\sf{ \bullet \: v_1 = velocity \: of \: bullet}\\\sf{ \bullet \: v_2 = velocity \: of \: rifle} \end{cases}$

$\longrightarrow \sf \:m_1 \times 100 = 2.5 \times 1 \\ \\ \longrightarrow \sf \:100m_1 = 2.5 \\ \\ \longrightarrow \sf \:m_1 = \frac{2.5}{100} \\ \\ \longrightarrow \sf \:m_1 = 0.025kg$

$\huge\dag\purple{\underline{\sf\: Hence}}$

• $\textsf{Mass of bullet is 0.025kg }$

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