a bullet leaves a rifle with a velocity of 100m/s and the rifle of mass 2.5 kg recoils with a velocity of 1m/s.find the mass of the bullet.
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Answered by
23
Hello!
Conservation of Momentum :
m₁v₁ = m₂v₂
⇒ m₁ = m₂v₂ / v₁
⇒ m₁ = (2.5 × 1) / 100
⇒ m₁ = 0.025 kg
⇒ m₁ = 25 g
Cheers!
Conservation of Momentum :
m₁v₁ = m₂v₂
⇒ m₁ = m₂v₂ / v₁
⇒ m₁ = (2.5 × 1) / 100
⇒ m₁ = 0.025 kg
⇒ m₁ = 25 g
Cheers!
Answered by
6
ANSWER :-
Applying the conservation of momentum to the problem we get,
==>m1v1 = m2v2(where m1v1 and m2v2 are the momentums of the bullet and rifle respectively)
=>m1 = m2v2 / v1
=>m1 = (2.5 * 1) / 100
=>m1 = 0.025kg
=>m1 = 25g
==>Mass of bullet is 25g.
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