Question

A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of
the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet

Answer 1

Answer:

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Answer 2

Given,

Leaves the rifle with a velocity of = 452 m/s

Moved a distance of = 0.93 m

To find,

The acceleration of the bullet.

Solution,

We can simply solve this numerical problem by using the following process.

Here,

The initial velocity of the bullet (u) = 0 m/s [As, it was initially at rest.]

Final velocity of th bullet (v) = 452 m/s

Displacement (s) = 0.93 m

Acceleration (a) = ?

Now, according to the kinematics -

v² = u²+2as

(452)²= (0)²+(2×a×0.93)

(2×a×0.93) = (452)²

1.86 × a = 204304

a = 109840.86 m/s²

a = 1.0984086 × 10⁵ m/s²

a ≈ 1.1 × 10⁵ m/s²

Hence, the acceleration of the bullet is approximately 1.1 × 10⁵ m/s²