Question

A bullet leaves tge rifle with a speed of 160m/s .lf the rifle is fixed horizontally at a height of 20m from the ground ,find the maximum distance the bullet can cover?​

Answer 1

Answer:

0.076m

Explanation:

Initial velocity of bullet(u) = 0m/s.

Final velocity of bullet (v) = 160m/s.

Height of rifle from the ground(s). = 20m.

finding the value of time.

$t = \frac{s}{v}$

$t = \frac{20}{160}$

so, we get 0.125s.

$s = ut + \frac{1}{2} at {}^{2}$

$s = \frac{1}{2} at {}^{2}$

Value of a = 9.8 (acceleration due to gravity).

$s = \frac{1}{2} \times 9.8 \times 0.125 \times 0.125$

By solving above formula, we get

S = 0.076m.

Hence the ballet goes 0.076m far.