Question

A bullet leaves tge rifle with a speed of 160m/s .the max horizontal distance covered by bullet is g=10

Answer 1

Answer:

we know from oblique projectile motion, 

range is given by  

where u is the initial velocity of projectile,  is the angle of inclination and g is the acceleration due to gravity.

for maximum value of range , 

 should be maximum

we know, maximum value of sine function is 1

so, at  = 45° range is maximum.

Therefore, 

here , u = 160m/s and g = 10 m/s² 

so, maximum range = (160)²/10 = 2560m

and maximum height , 



H = (160)²/40 = 640m

hence, greatest distance = 2560m

and height = 640m







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